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return 0; } void divide(double a, double b) { try { if(!b) throw b; // check for divide-by-zero cout << "Result: " << a/b << endl; } catch (double b) { cout << "Can't divide by zero\n"; } }
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While the preceding program is a very simple example, it does illustrate the essential nature of exception handling Since division by zero is illegal, the program cannot continue if a zero is entered for the second number In this case, the exception is handled by not performing the division (which would have caused abnormal program termination) and by notifying the user of the error The program then reprompts the user for two more numbers Thus, the error has been handled in an orderly fashion and the user may continue on with the program The same basic concepts will apply to more complex applications of exception handling Exception handling is especially useful for exiting from a deeply nested set of routines when a catastrophic error occurs In this regard, C++ s exception handling is designed to replace the rather clumsy C-based setjmp( ) and longjmp( ) functions The key point about using exception handling is to provide an orderly means of handling errors This means rectifying the situation, if possible
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Using run-time type identification, you can determine the type of an object during program execution To obtain an object s type, use typeid You must include the header <typeinfo> in order to use typeid Its general form is shown here typeid(object) Here, object is the object whose type you will be obtaining typeid returns a reference to an object of type type_info that describes the type of object defined by object The type_info class defines the following public members:
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bool operator==(const type_info & ob ) const; bool operator!=(const type_info & ob ) const; bool before(const type_info & ob ) const; const char *name( ) const; The overloaded == and != provide for the comparison of types The before( ) function returns true if the invoking object is before the object used as a parameter in collation order (This function is mostly for internal use only Its return value has nothing to do with inheritance or class hierarchies) The name( ) function returns a pointer to the name of the type When typeid is applied to a base class pointer of a polymorphic class, it will automatically return the type of the object being pointed to, which might be a class derived from that base (Remember, a polymorphic class is one that contains at least one virtual function) Thus, using typeid, you can determine at run time the type of the object that is being pointed to by a base class pointer The following program demonstrates this principle
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// An example that uses typeid #include <iostream> #include <typeinfo> using namespace std; class BaseClass { int a, b; virtual void f() {}; // make BaseClass polymorphic }; class Derived1: public BaseClass { int i, j; }; class Derived2: public BaseClass { int k; }; int main() { int i; BaseClass *p, baseob; Derived1 ob1; Derived2 ob2;
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Borland C++ Builder: The Complete Reference
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// First, display type name of a built in type cout << "Typeid of i is "; cout << typeid(i)name() << endl; // Demonstrate typeid with polymorphic types p = &baseob; cout << "p is pointing to an object of type "; cout << typeid(*p)name() << endl; p = &ob1; cout << "p is pointing to an object of type "; cout << typeid(*p)name() << endl; p = &ob2; cout << "p is pointing to an object of type "; cout << typeid(*p)name() << endl; return 0; }
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